Law of cos:
a^2 = b^2 +c^2 - 2bc cos A b^2 = a^2 + c^2 - 2ac cos B
c^2 = a^2 + b^2 - 2ab cos C
the law of cosines
a2=b2+c2-2bc cosA
b2=a2+c2-2ac cos B
c2=a2+b2-2ac cos C
What is cosine of 60 degrees?
What is the sine of 60 degrees?
Solve: c^2= 2^2 + 3^2 - 2x2x3 cos27
(Cos,Sin)
To find: Sin = Opposite/Hypotenuse Cos =Adjacent/Hypotenuse Tan = Opposite/Adjacent
Suppose three campsites are in a triangle. The campers communicate by using a two way radio with a range about 1 mile, or 5280 ft. Will the campers at sites one and three are able to communicate directly with each other.
Use the law of cosines:
b^2 = a^2 + c^2 - 2ac Cos B
b^2 = 3900^2 + 3400^2 - 2(3900)(3400) Cos 86
b^2 = 24,920,058
b = 4992 ft
a^2 = b^2 +c^2 - 2bc cos A b^2 = a^2 + c^2 - 2ac cos B
c^2 = a^2 + b^2 - 2ab cos C
the law of cosines
a2=b2+c2-2bc cosA
b2=a2+c2-2ac cos B
c2=a2+b2-2ac cos C
What is cosine of 60 degrees?
What is the sine of 60 degrees?
Solve: c^2= 2^2 + 3^2 - 2x2x3 cos27
(Cos,Sin)
To find: Sin = Opposite/Hypotenuse Cos =Adjacent/Hypotenuse Tan = Opposite/Adjacent
Suppose three campsites are in a triangle. The campers communicate by using a two way radio with a range about 1 mile, or 5280 ft. Will the campers at sites one and three are able to communicate directly with each other.
Use the law of cosines:
b^2 = a^2 + c^2 - 2ac Cos B
b^2 = 3900^2 + 3400^2 - 2(3900)(3400) Cos 86
b^2 = 24,920,058
b = 4992 ft